Determine The Acceleration That Result When A 12n Net Force Is Applied A 3kg Object Ad Then To A 6kg Object

Determine the acceleration that result when a 12n Net force is applied a 3kg object ad then to a 6kg object

 

Using the formula from Newtons second law of motion: fnet = m x a

We can find a using the formula: a =  fnet / m

Then, substitute: a = 12n / 3kg

We have: a = 4 m/s^2

And for the 6 kg we have: a = 12n / 6kg

a = 2 m/s^2